In a circuit with two resistors in series, each 6 Ω, connected to a 12 V battery, what is the current?

In a circuit with two resistors in series, each 6 Ω, connected to a 12 V battery, what is the current?

• A. 0.5 A
• B. 1 A
• C. 2 A
• D. 3 A

Answer: (B)

In a series circuit, the same current flows through every component, and the total resistance is the sum of the individual resistances. Here, two 6 Ω resistors in series add up to 12 Ω. With a 12 V source, the current is I = V/R = 12 V / 12 Ω = 1 A. So the current through the circuit is 1 ampere. If you check voltage distribution, each resistor would drop about 6 V since the resistances are equal, but the current remains the same through both.

In a series circuit, the same current flows through every component, and the total resistance is the sum of the individual resistances. Here, two 6 Ω resistors in series add up to 12 Ω. With a 12 V source, the current is I = V/R = 12 V / 12 Ω = 1 A. So the current through the circuit is 1 ampere. If you check voltage distribution, each resistor would drop about 6 V since the resistances are equal, but the current remains the same through both.