If resistance remains constant, doubling the voltage increases the power by a factor of four.

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Prepare for the Abeka Science Matter and Energy Test 7. Utilize flashcards and multiple choice questions with detailed explanations to boost your comprehension and succeed in your exam!

Multiple Choice

If resistance remains constant, doubling the voltage increases the power by a factor of four.

Explanation:
When resistance stays the same, power in a resistor scales with the square of the voltage. Using P = V^2 / R, if you double the voltage, you get P' = (2V)^2 / R = 4V^2 / R = 4P. So power increases by a factor of four. (Equivalently, with P = I^2R and V = IR, doubling V doubles I, and P = I^2R becomes four times larger as well.) If the resistance isn’t constant, the factor could differ.

When resistance stays the same, power in a resistor scales with the square of the voltage. Using P = V^2 / R, if you double the voltage, you get P' = (2V)^2 / R = 4V^2 / R = 4P. So power increases by a factor of four. (Equivalently, with P = I^2R and V = IR, doubling V doubles I, and P = I^2R becomes four times larger as well.) If the resistance isn’t constant, the factor could differ.

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